Matthew Otwinowski
Scaling Analysis Of Acid Rock Drainage
APPENDIX A
Numerical results for the chemical kinetics at different pH values
Fig. A1. The oxidation kinetics due to reactions (R1)-(R4) for different temperatures; S/V=10 m2/l and the initial conditions: [Fe2+(t=0)]=0, [SO42-(t=0)]=0, [Fe(OH)3(t=0)]=0 and pH(t=0)=7. Constant in time concentration of dissolved oxygen, [O2] for [O2]gas=21%. Horizontal axis: time in seconds, vertical axis: concentration in moles per litre. (180 000 sec = 5 hours). |
| Fig. A2. The oxidation kinetics due to reactions (R1)-(R4) for different temperatures, S/V=1 m2/l; the initial conditions: [Fe2+(t=0)]=0, [SO42-(t=0)]=0, [Fe(OH)3(t=0)]=0. Constant in time pH(t=0)=6.9 concentration of dissolved oxygen, [O2] for [O2]gas=21%. Horizontal axis: time in seconds, vertical axis:concentration in moles per litre. (1 800 000 sec = 3 weeks). |
| Fig. A3. The oxidation kinetics due to reactions (R1)-(R4) for different temperatures, S/V=1 m2/l; the initial conditions: [Fe2+(t=0)]=0, [SO42-(t=0)]=0, [Fe(OH)3(t=0)]=0. Constant in time pH(t=0)=6.3 concentration of dissolved oxygen, [O2] for [O2]gas=21%. Horizontal axis: time in seconds, vertical axis: concentration in moles per litre. (1 800 000 sec = 3 weeks). |
| Fig. A4. The consumption of dissolved oxygen at pH=6.9 for different values of S/V and different temperatures. (a) S/V=1m2/l, T=283 K; (b) S/V=1m2/l, T=303 K; (c) S/V=1m2/l, T=323 K; (d) S/V=10m2/l, T=303 K. Horizontal axis: time in seconds; vertical axis: concentration in moles per litre (3 000 000 s = 35 days). |
| Fig. A5. The consumption of dissolved oxygen at pH=5.5 for different values of S/V and different temperatures. (a) S/V=1m2/l, T=283 K; (b) S/V=1m2/l, T=303 K; (c) S/V=1m2/l, T=323 K; (d) S/V=10m2/l, T=303 K. Horizontal axis: time in seconds; vertical axis: concentration in moles per litre (3 000 000 s = 35 days). |
This post first appeared on Maciej Otwinowski - Synergetic Technology, please read the originial post: here
