By using 'vararg' modifier, you can define a function that Takes Variable Number of arguments. If you would like to know, basics of vararg in Java, you can go through my below post.
https://self-learning-java-tutorial.blogspot.com/2014/02/varargs-methods-with-variable-number-of.html
Ex
fun sumOf(vararg numbers: Int): Int {
}
Above function takes variable number of integer arguments and return an integer.
VarargsDemo.kt
fun sumOf(vararg numbers: Int): Int {
var sum: Int = 0;
for (i in numbers) {
sum = sum + i
}
return sum
}
fun main(args: Array) {
println("Sum of (1, 2, 3) : ${sumOf(1, 2, 3)}")
println("Sum of (13, 22, 13, 5, 3) : ${sumOf(13, 22, 13, 5, 3)}")
}
Output
Sum of (1, 2, 3) : 6
Sum of (13, 22, 13, 5, 3) : 56
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