Note: The general equation of circle is where the center is and radius
Question 1: Find the coordinates of the center and radius of each of the following circles :
i) ii)
iii) iv)
Answer:
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i) Give equation :
Comparing it with , we get,
Therefore center
Radius
ii) Give equation :
Comparing it with , we get,
Therefore center
Radius
iii) Given equation
Comparing it with , we get,
Therefore center
Radius
iv) Given equation
Comparing it with , we get,
Therefore center
Radius
Question 2: Find the equation of the circle passing through the points:
(i) and (ii) ,and
(iii) and (iv) and
Answer:
(i) The circle passes through the points and
The equation of circle is … … … … … i)
Substituting in i) we get
… … … … … ii)
Substituting in i) we get
… … … … … iii)
Substituting in i) we get
… … … … … iv)
Solving ii) , iii) and iv) simultaneously, we get
Therefore the equation of the required circle is:
(ii) The circle passes through the points ,and
The equation of circle is … … … … … i)
Substituting in i) we get
… … … … … ii)
Substituting in i) we get
… … … … … iii)
Substituting in i) we get
… … … … … iv)
Solving ii) , iii) and iv) simultaneously, we get
Therefore the equation of the required circle is:
(iii) The circle passes through the points and
The equation of circle is … … … … … i)
Substituting in i) we get
… … … … … ii)
Substituting in i) we get
… … … … … iii)
Substituting in i) we get
… … … … … iv)
Solving ii) , iii) and iv) simultaneously, we get
Therefore the equation of the required circle is:
(iv) The circle passes through the points and
The equation of circle is … … … … … i)
Substituting in i) we get
… … … … … ii)
Substituting in i) we get
… … … … … iii)
Substituting in i) we get
… … … … … iv)
Solving ii) , iii) and iv) simultaneously, we get
Therefore the equation of the required circle is:
Question 3: Find the equation of the circle which passes through and has its center on the line .
Answer:
The circle passes through and has its center on the line .
The equation of circle is … … … … … i)
Substituting in i) we get
… … … … … ii)
Substituting in i) we get
… … … … … iii)
Since center lie on , we get
… … … … … iv)
Solving ii) , iii) and iv) simultaneously, we get
Therefore the equation of the required circle is:
Question 4: Find the equation of the circle which passes through the points and has its center on the line .
Answer:
The circle passes through and has its center on the line .
The equation of circle is … … … … … i)
Substituting in i) we get
… … … … … ii)
Substituting in i) we get
… … … … … iii)
Since center lie on , we get
… … … … … iv)
Solving ii) , iii) and iv) simultaneously, we get
Therefore the equation of the required circle is:
Question 5: Show that the points and are concyclic.
Answer:
Consider and
The equation of circle is … … … … … i)
Substituting in i) we get
… … … … … ii)
Substituting in i) we get
… … … … … iii)
Substituting in i) we get
… … … … … iv)
Solving ii) , iii) and iv) simultaneously, we get
Therefore the equation of the required circle is:
… … … … … v)
Now we check if satisfies equation v)
. Therefore S lies on the circle.
Therefore, and are con-cyclic.
Question 6: Show that the points and all lie on a circle, and find its equation, center and radius.
Answer:
Consider and
The equation of circle is … … … … … i)
Substituting in i) we get
… … … … … ii)
Substituting in i) we get
… … … … … iii)
Substituting in i) we get
… … … … … iv)
Solving ii) , iii) and iv) simultaneously, we get
Therefore the equation of the required circle is:
… … … … … v)
Now we check if satisfies equation v)
. Therefore S lies on the circle.
Therefore, and are con-cyclic.
Therefore center
Radius units.
Question 7: Find the equation of the circle which circumscribes the triangle formed by the lines:
i) and
ii) and
iii) and iv) and
Answer:
i) Given equations:
… … … … … i)
… … … … … ii)
… … … … … iii)
Solving i) , ii) and iii) we get the vertices
The equation of circle is … … … … … iv)
Substituting in iv) we get
… … … … … v)
Substituting in iv) we get
… … … … … vi)
Substituting in iv) we get
… … … … … vii)
Solving v) , vi) and vii) simultaneously, we get
Therefore the equation of the required circle is:
ii) Given equations:
… … … … … i)
… … … … … ii)
… … … … … iii)
Solving i) , ii) and iii) we get the vertices
The equation of circle is … … … … … iv)
Substituting in iv) we get
… … … … … v)
Substituting in iv) we get
… … … … … vi)
Substituting
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