Question 1: Find the Amount and the Compound interest on Rs.12000 in 3 years at 5%; interest being compounded annually.

Answer:

Question 2: Calculate the amount, if Rs.15000 is lent at compound interest for 2 years and the rates for the successive years are 8% p.a. and 10% p.a. respectively.

Answer:

Question 3: Calculate the compound interest accrued on Rs.6000 in 3 years, compounded yearly, if the rates for the successive years are 5%, 8% and 10% respectively.

Answer:

Question 4: What sum of money will amount to Rs.5445 in 2 years at 10% per annum compound interest?

Answer:

Question 5: On what sum of money will be compound interest for 2 years at 5 per cent per annum amount to Rs,768.75?

Answer:

Question 6: Find the sum on which the compound interest for 3 years at 10% per annum amounts to Rs.1655.

Answer:

Question 7: What principal will amount to Rs.9856 in two years, if the rates of interest for Question successive years are 10% and 12% respectively?

Answer:

Question 8: On a certain sum, the compound interest in 2 years amounts to Rs.4240. If the rates of interest for successive year are 10% and 15% respectively, find the sum.

Answer:

Question 9: At what rate per cent per annum will Rs.6000 amount to Rs.6615 in 2 years when interest is compounded annually?

Answer:

Question 10: At what rate per cent compound interest, does a sum of money become 1.44 times of itself in 2years?

Answer:

Question 11: At what rate per cent will a sum of Rs.4000 yield Rs.1324 as compound interest in 3 years?

Answer:

Given

Question 12: A person invests Rs.5000 for three years at a certain rate of interest compounded annually. At the end of two years this sum amounts to Rs.6272. Calculate;

- The rate of interest per annum
- The amount at the end of the third year.

Answer:

At the end of third year

Question 13: In how many years will Rs.7000 amount to Rs.9317 at 10% per cent per annum compound interest?

Answer:

Question 14: Find the time, in years, in which Rs.4000 will produce Rs.630.50 as compound interest at 5% p.a. interest being compounded annually.

Answer:

Question 15: Divide Rs.28,730 between A and B so that when their shares are lent out at 10% compound interest compounded per year, the amount that A receives in 3 years is the same as what B receives in 5 years.

Answer:

Let the share of A = x Rs. Therefore share of B = (28730-x) Rs.

For A

For B

Given

Therefore B’s share =

Question 16: A sum of Rs.34522 is divided between A and B, 18 years and 21 years old respectively in such a way that if their shares be invested at 5% per annum compound interest, both will receive equal money at the age of 30 years. Find the shares of each out of Rs.34522.

Answer:

Let the share of A = x Rs. Therefore share of B = (34522-x) Rs.

For A

For B

Given

Therefore B’s share =

Question 17: A sum of Rs.44200 is divided between A and B, 12 years and 14 years old respectively, in such a way that if their portions be invested at 10% per annum compound interest, they will receive equal amounts on reaching 16 years of age.

- What is the share of each out of Rs.44200?
- What will each receive, when 16 years old?

Answer:

Let the share of A = x Rs. Therefore share of B = (44200-x) Rs.

For A

For B

Given

Therefore B’s share =

Question 18: At the beginning of year 2011, a man had Rs.22000 in his bank account. He saved some money by the end of this year and deposited it in the bank. The bank pays 10% per annum compound interest and at the end of year 2012 he had Rs.39820 in his bank account. Find, what amount of money at the end of year 2011.

Answer:

year 2011

Lets us say he saves and deposits at the end of year 2011.

Question 19: If the amounts of two consecutive years on a sum of money are in the ratio 20:21, find the rate of interest.

Answer:

Given

Question 20: On what sum of money will the difference between the compound interest and simple interest for 3 years be equal to Rs.930, if the rate of interest charged for both is 10% p.a.?

Answer:

Let the

Simple Interest

Compound Interest

Given

*This post first appeared on Icse Mathematics « MATHEMATICS MADE EASY FOR STUDENTS, please read the originial post: here*