2√150 – 3√54 – √294 + 3√486
=> 2√(25 x 6) – 3√(9 x 6) – √(49 x 6) + 3√(81 x 6)
=> 10√6 – 9√6 – 7√6 + 27√6
=> √6 + 20√6 = 21√6
=> 2√(25 x 6) – 3√(9 x 6) – √(49 x 6) + 3√(81 x 6)
=> 10√6 – 9√6 – 7√6 + 27√6
=> √6 + 20√6 = 21√6
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Originally posted 2022-06-05 10:02:30.
