4 (c+d) + 3 (3c + 2d)
= (4 × c) (4 × d) + (3 ×3c) (3 × 2d)
= 4c + 4d + 9c + 6d
= 4c + 9c + 4d + 6d
= 13c + 10d
= (4 × c) (4 × d) + (3 ×3c) (3 × 2d)
= 4c + 4d + 9c + 6d
= 4c + 9c + 4d + 6d
= 13c + 10d
Originally posted 2022-06-05 10:00:19.
Originally posted 2022-06-05 10:00:19.
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