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How to make a #define of function calls which have trailing arguments?

I have functions with trailing arguments like so:
void myFunction(const unsigned char *src, int src_len, unsigned char *dst, int dst_len);

When I try to use the function like this:
void myFunction(const unsigned char *src, int src_len, unsigned char *dst, int dst_len, int test);

I get this error: “undefined reference to `myFunction'”
Which is not surprising – but I don’t know how to make a #define of this.

I’m assuming your code is quite simple, and that if you’re using gcc, you’re also using C++:
#ifdef __cplusplus
#define myFunction(…) myFunction(__VA_ARGS__,__VA_ARGS__)
#else
#define myFunction(…) myFunction(__VA_ARGS__, __VA_ARGS__)
#endif

(I also assume that the explicit arguments are just dummy arguments for the function.)
In C++, you can declare a function as taking an arbitrary number of arguments:
void myFunction(const unsigned char *src, int src_len,
unsigned char *dst, int dst_len,
int test);

Using the above is just a shorthand: you write
myFunction(…);

instead of
myFunction(…,…,…,…);

and you can write
void myFunction(const unsigned char *src, int src_len,
unsigned char *dst, int dst_len,
int test);

(You don’t have to use the comma though.)
Because __VA_ARGS__ expands to all the remaining arguments, you can put

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