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C++ program to find count of divisors in n!

c++ programs

In this Program, we are going to share a C++ program to find count of divisors in n!. If you are a beginner and want to start learning the C++ programming, then keep your close attention in this tutorial as I am going to share a program for C++ program to find count of divisors in n!.

  • Collection of 100+ C++ problems with solutions.

C++ program to find count of divisors in n!

Copy the below C++ program and execute it with the help of GCC compiler. At the end of this program, We have shared the output of this program.

#include 

using namespace std; 

typedef unsigned long long int ull; 
  
vector allPrimes; 
  
// Fills above vector allPrimes[] for a given n 
void sieve(int n) 
{ 
    // Create a boolean array "prime[0..n]" and 
    // initialize all entries it as true. A value 
    // in prime[i] will finally be false if i is 
    // not a prime, else true. 
    vector prime(n+1, true); 
  
    // Loop to update prime[] 
    for (int p=2; p*p

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C++ program to find count of divisors in n!

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