Note: When slope and a point is given, the equation of the line is
Question 1: Find the Equation of the straight line passing through the point and having slope .
Answer:
Here and
Substituting in we get
Hence the equation of the straight line is
Question 2: Find the equation of the straight line passing through and inclined at an angle of with the x-axis.
Answer:
Here and
Substituting in we get
Hence the equation of the straight line is
Question 3: Find the equation of the line passing through with slope .
Answer:
Here and
Substituting in we get
Hence the equation of the straight line is
Question 4: Find the equation of the line passing through and inclined with x-axis at an angle of .
Answer:
Here
Also
Substituting in we get
Hence the equation of the straight line is
Question 5: Find the equation of the straight line which passes through the point and makes such an angle with the positive direction of x-axis whose sine is
Answer:
Given
We know,
Therefore and
Substituting in we get
Hence the equation of the straight line is
Question 6: Find the equation of the straight line passing through and making an angle of with the positive direction of y-axis
Answer:
Slope of line and
Substituting in we get
Hence the equation of the straight line is
Question 7: Find the lines through the point making angle and with the x-axis. Also, find the lines parallel to them cutting the y-axis at a distance of units below the origin.
Answer:
Given
Also
Therefore the equation passing through and having and slope respectively are
Now let us find lines parallel to these lines but passing through
Therefore the equation passing through and having and slope respectively are
Question 8: Find the equations of the straight lines which cut off an intercept from the y-axis and are equally inclined to the axes.
Answer:
Given the lines are equally inclined to the axes.
Hence, their inclination with positive x-axis are and
Therefore for Line 1:
and for Line 2:
Hence the equation of Line 1:
And the equation for Line 2:
Question 9: Find the equation of the line which intercepts a length on the positive direction of the x-axis and is inclined at an angle of with the positive direction of y-axis.
Answer:
Here and
Therefore equation of the line is:
Question 10: Find the equation of the straight line which divides the join of the points and in the ratio and is also perpendicular to it.
Answer:
Given points and
Therefore slope of
Slope of line to
The coordinate of the point that divides AB in the ratio of is
Therefore the equation of the required line:
Question 11: Prove that the perpendicular drawn from the point on the join of and divides it in the ratio .
Answer:
Given points and
Slope of
is to . Therefore slope of
Therefore equation of is:
… … … … … i)
Equation of :
… … … … … ii)
Point of intersection will be found by solving the two equations.
Multiply i) by and ii) by and then subtract ii) from i) we get
Substituting in i) we get
Hence the point of intersection is
Therefore we see that divides AB in the ratio of
Question 12: Find the equations to the altitudes of the triangle whose angular points ate and .
Answer:
Given and .
Let , and are the altitudes as shown in the figure.
Slope of
Therefore slope of
Therefore equation of :
Slope of
Therefore slope of
Therefore equation of :
Slope of
Therefore slope of
Therefore equation of :
Question 13: Find the equation of the right bisector of the line segment joining the points and .
Answer:
Given points and
Therefore the midpoint of
Slope of
Therefore the slope of the bisector
Hence the equation of the bisector:
Hence the equation of the right bisector is
Question 14: Find the equation of the line passing through the point and perpendicular to the line joining and .
Answer:
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