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set all css3 background-image with jquery

set all css3 background-image with jquery

Problem

hi I want to set the background-image for all browser with jquery :

background-image:linear-gradient(green, blue); /* Norme W3C */
background-image:-moz-linear-gradient(green, blue); /* Firefox */
background-image:-webkit-gradient(linear, green, blue); /* Chrome, Safari */
background-image:-o-linear-gradient(green, blue); /* Opera */
background-image:-ms-linear-gradient(green, blue); /* IE */

and I set it like that :

$("#"+elmt).css("background-image" , "linear-gradient("+hex+","+$('#test2').val()+")" );

only for W3C but it work on firefox but not on Chrome.

How can I set all this setting?

Problem courtesy of: user1804164

Solution

From the jQuery 1.8 Blog's release

Automatic CSS prefixing: When you use a CSS property, in either .css() or .animate(), we’ll use the correct prefixed property (when appropriate) for that browser. For example, take .css("user-select", "none"); in Chrome/Safari we’ll set the value as "-webkit-user-select", Firefox will use "-moz-user-select", and IE10 will use "-ms-user-select".

Upgrade to the latest version and this should be handled automatically.

Edit

This should work automatically, the following should be implemented in jQuery 1.8,

var cssPrefixString = {};
var cssPrefix = function(propertie) {
    if (cssPrefixString[propertie] || cssPrefixString[propertie] === '') return cssPrefixString[propertie] + propertie;
    var e = document.createElement('div');
    var prefixes = ['', 'Moz', 'Webkit', 'O', 'ms', 'Khtml']; // Various supports...
    for (var i in prefixes) {
        if (typeof e.style[prefixes[i] + propertie] !== 'undefined') {
            cssPrefixString[propertie] = prefixes[i];
            return prefixes[i] + propertie;
        }
    }
    return false;
};

The usage

var cssTransform = cssPrefix('Transform'); // "MozTransform" or "WebkitTransform"
if (cssTransform ) {
    var cssProp = {};
    cssProp['border'] = '1px solid rgba(0, 0, 0, .5)';
    cssProp[cssPrefix('Transform')] = 'rotate(20deg)';
    cssProp[cssPrefix('borderRadius')] = '5px'; // Keep the camelCaze (jQuery like)
    cssProp[cssPrefix('boxShadow')] = '2px 2px 6px grey';
    $('div#myDiv').css(cssProp);
    // console.log(cssProp);
}

Which came from the link -- a working jsFiddle

So one of these two methods should work for you.

Solution courtesy of: Ohgodwhy

Discussion

View additional discussion.



This post first appeared on CSS3 Recipes - The Solution To All Your Style Problems, please read the originial post: here

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set all css3 background-image with jquery

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